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Mathematics

On what sum of money will the difference between simple interest and compound interest for 2 years at 5% per annum be equal to ₹ 50 ?

Compound Interest

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Answer

Let P be the sum of money.

R = 5 %, T = 2 years

S.I.=P×R×T100=P×5×2100=10P100=P10=0.1P\text{S.I.} = \dfrac{P \times R \times T}{100}\\[1em] = \dfrac{P \times 5 \times 2}{100}\\[1em] = \dfrac{10P}{100}\\[1em] = \dfrac{P}{10} = 0.1P

C.I. = P (1+R100)n\Big(1 + \dfrac{R}{100}\Big)^n - P

= P x (1+5100)2\Big(1 + \dfrac{5}{100}\Big)^2 - P

= P x (1+0.05)2\Big(1 + 0.05\Big)^2 - P

= P x (1.05)2(1.05)^2 - P

= 1.1025P - P

= 0.1025P

The difference between S.I. and C.I. = C.I. - S.I. = 50

⇒ 50 = 0.1025P - 0.1P

⇒ 50 = 0.0025P

⇒ P = 500.0025\dfrac{50}{0.0025}

⇒ P = 5,00,00025\dfrac{5,00,000}{25}

⇒ P = 20,000

Hence, the sum of money = ₹ 20,000.

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