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Mathematics

Find the difference between simple interest and compound interest on ₹ 4,000 for two years at 10% per annum.

Compound Interest

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Answer

P = ₹ 4,000, R = 10 %, T = 2 years

S.I.=P×R×T100=4,000×10×2100=80,000100=800\text{S.I.} = \dfrac{P \times R \times T}{100}\\[1em] = \dfrac{4,000 \times 10 \times 2}{100}\\[1em] = \dfrac{80,000}{100}\\[1em] = 800

C.I. = P (1+R100)n\Big(1 + \dfrac{R}{100}\Big)^n - P

= 4,000 x (1+10100)2\Big(1 + \dfrac{10}{100}\Big)^2 - 4,000

= 4,000 x (1+0.1)2\Big(1 + 0.1\Big)^2 - 4,000

= 4,000 x (1.1)2(1.1)^2 - 4,000

= 4,000 x 1.21 - 4,000

= 4,840 - 4,000

= 840

The Difference between C.I. and S.I. = ₹ 840 - 800 = ₹ 40

Hence, the difference between simple interest and compound interest = ₹ 40.

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