Potassium (at No. 19) and chlorine (at No.17) react to form a compound. Explain on the basis of electronic concept :

(i) oxidation

(ii) reduction

(iii) oxidising agent

(iv) reducing agent.

The electronic configuration of:

Potassium (19) = 2, 8, 8, 1

Chlorine (17) = 2, 8, 7

The reaction is :

2K + Cl₂ ⟶ K⁺ + 2Cl^-

(i) Oxidation : 2K ⟶ K⁺
    Potassium undergoes oxidation reaction as it loses an electron.

(ii) Reduction : Cl₂ ⟶ 2Cl^-
     Chlorine undergoes reduction reaction as it gains an electron.

(iii) Chlorine acts as an oxidising agent and gets reduced.

(iv) Potassium acts as a reducing agent and gets oxidised.