Chemistry
Divide the following redox reactions into oxidation and reduction half reactions.
(i) Zn + Pb2+ ⟶ Zn2+ + Pb
(ii) Zn + Cu2+ ⟶ Zn2+ + Cu
(iii) Cl2 + 2Br- ⟶ Br2 + 2Cl-
(iv) Sn2+ + 2Hg2+ ⟶ Sn4+ + Hg22+
(v) 2Cu+ ⟶ Cu + Cu2+
Chemical Bonding
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Answer
(i) Oxidation : Zn ⟶ Zn2+
Reduction : Pb2+ ⟶ Pb
(ii) Oxidation : Zn ⟶ Zn2+
Reduction : Cu2+ ⟶ Cu
(iii) Oxidation : 2Br- ⟶ Br2
Reduction : Cl2 ⟶ 2Cl-
(iv) Oxidation : Sn2+ ⟶ Sn4+
Reduction : 2Hg2+ ⟶ Hg22+
(v) Oxidation : Cu+ ⟶ Cu2+
Reduction : Cu+ ⟶ Cu
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