Mathematics
On a map drawn to scale of 1 : 2,50,000; a triangular plot of land has the following measurements : AB = 3 cm, BC = 4 cm and angle ABC = 90°.
Calculate :
(i) the actual length of AB and BC in km
(ii) the area of the plot in sq. km.
Similarity
8 Likes
Answer
(i) Given,
Scale factor for reduction (k) =
⇒ Length of AB in model = k × Length of AB
⇒ 3 = × Length of AB
⇒ Length of AB = 3 × 250000 = 750000 cm = = 7.5 km.
⇒ Length of BC in model = k × Length of BC
⇒ 4 = × Length of BC
⇒ Length of BC = 4 × 250000 = 1000000 cm = = 10 km.
Hence, actual length of AB = 7.5 km and BC = 10 km.
(ii) Area of plot = base × height
= × BC × AB
= × 10 × 7.5
= 37.5 sq. km.
Hence, area of plot = 37.5 sq. km.
Answered By
4 Likes
Related Questions
In the given figure, ABC is a right angled triangle with ∠BAC = 90°.
(i) Prove that : △ADB ~ △CDA.
(ii) If BD = 18 cm and CD = 8 cm, find AD.
(iii) Find the ratio of the area of △ADB is to area of △CDA.
ABC is a right angled triangle with ∠ABC = 90°. D is any point on AB and DE is perpendicular to AC. Prove that :
(i) △ADE ~ △ACB
(ii) If AC = 13 cm, BC = 5 cm and AE = 4 cm. Find DE and AD.
(iii) Find, area of △ADE : area of quadrilateral BCED.
Given : AB || DE and BC || EF. Prove that :
(i)
(ii) △DFG ~ △ACG.
PQR is a triangle. S is a point on the side QR of △PQR such that ∠PSR = ∠QPR. Given QP = 8 cm, PR = 6 cm and SR = 3 cm.
(i) Prove △PQR ~ △SPR.
(ii) Find the lengths of QR and PS.
(iii)