Mathematics
On a graph paper, draw the lines x = 3 and y = -5. Now, on the same graph paper, draw the locus of the point which is equidistant from the given lines.
Locus
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Answer
Steps of construction :
Draw a line l with equation x = 3 and m having equation y = -5.
Let these lines intersect at point P.
Draw a line n, which is the angle bisector of ∠P.
Since, n is the angle bisector of ∠P so any point on n is equidistant from l and m.
Hence, locus of the point which is equidistant from the given lines is line n..
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(i) Construct a triangle ABC, in which BC = 6 cm, AB = 9 cm, and ∠ABC = 60°.
(ii) Construct the locus of all points, inside △ABC, which are equidistant from B and C.
(iii) Construct the locus of the vertices of the triangles with BC as base, which are equal in area to △ABC.
(iv) Mark the point Q, in your construction, which would make △QBC equal in area to △ABC, and isosceles.
(v) Measure and record the length of CQ.