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Mathematics

Mohit and Arjun are friends and were born in the year 2005. The probability that they were born on different days is :

  1. 1

  2. 0

  3. 1365\dfrac{1}{365}

  4. 364365\dfrac{364}{365}

Probability

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Answer

No. of days in an year = 365.

∴ No. of possible outcomes = 365.

If Mohit and Arjun were born on same day, then

∴ No. of favourable outcomes = 1

If Mohit and Arjun were born on different day, then

∴ No. of favourable outcomes (for different days) = 364 (365 - 1)

P(Mohit and Arjun were born on different days)

= No. of favourable outcomesNo. of possible outcomes=364365\dfrac{\text{No. of favourable outcomes}}{\text{No. of possible outcomes}} = \dfrac{364}{365}.

Hence, Option 4 is the correct option.

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