If x is a positive integer and 15 - 2(2x - 1) 15, the solution set is : 1. {-2, -1} 2. {1, 2, 3, 4, 5, ......} 3. {0, 1, 2, 3, 4, ......} 4. {1, 2, 3, 4, 5, 6}

Solving, ⇒ 15 - 2(2x - 1) 15 ⇒ 15 - 4x + 2 15 ⇒ 4x 15 - 15 + 2 ⇒ 4x 2 ⇒ x ⇒ x Since, x is a positive integer. So, x = {1, 2, 3, 4, 5, ......} Hence, Option 2 is the correct option.

Mathematics

If x is a positive integer and 15 - 2(2x - 1) < 15, the solution set is :
{-2, -1}
{1, 2, 3, 4, 5, ……}
{0, 1, 2, 3, 4, ……}
{1, 2, 3, 4, 5, 6}

Linear Inequations

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Answer

Solving,

⇒ 15 - 2(2x - 1) < 15

⇒ 15 - 4x + 2 < 15

⇒ 4x > 15 - 15 + 2

⇒ 4x > 2

⇒ x > $\dfrac{2}{4}$

⇒ x > $\dfrac{1}{2}$

Since, x is a positive integer.

So, x = {1, 2, 3, 4, 5, ……}

Hence, Option 2 is the correct option.

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Mathematics

If x is a positive integer and 15 - 2(2x - 1) < 15, the solution set is :
{-2, -1}
{1, 2, 3, 4, 5, ……}
{0, 1, 2, 3, 4, ……}
{1, 2, 3, 4, 5, 6}

Linear Inequations

Answer

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Mathematics

If x is a positive integer and 15 - 2(2x - 1) < 15, the solution set is :{-2, -1}{1, 2, 3, 4, 5, ……}{0, 1, 2, 3, 4, ……}{1, 2, 3, 4, 5, 6}

Linear Inequations

Answer

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From a solid cylinder of height h cm and base radius r cm, a conical cavity of the same height and same radius is drilled out.If the slant height of the conical cavity is l cm, the surface area of the remaining solid is :2πrh + πrl2πrh - πr2 + πrl2πrh + πrl + πr22πrh - πrl + πr2

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If x is a positive integer and 15 - 2(2x - 1) < 15, the solution set is :
{-2, -1}
{1, 2, 3, 4, 5, ……}
{0, 1, 2, 3, 4, ……}
{1, 2, 3, 4, 5, 6}

If in △ABC and △DEF, $\dfrac{AB}{DE} = \dfrac{BC}{FD}$ , then the two triangles will be similar to each other, if :
∠A = ∠F
∠B = ∠D
∠B = ∠E
∠A = ∠D

If m × $\begin{bmatrix$ , then the values of m and n are :
m = -3, n = -4
m = 3, n = -4
m = -3, n = 4
m = 3, n = 4

From a solid cylinder of height h cm and base radius r cm, a conical cavity of the same height and same radius is drilled out.
If the slant height of the conical cavity is l cm, the surface area of the remaining solid is :
2πrh + πrl
2πrh - πr² + πrl
2πrh + πrl + πr²
2πrh - πrl + πr²

Mohit and Arjun are friends and were born in the year 2005. The probability that they were born on different days is :
1
0
$\dfrac{1}{365}$
$\dfrac{364}{365}$