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In the given figure, PA = 14 cm, PC = 16 cm and CD = 18 cm, find the length of AB.

In the given figure, PA = 14 cm, PC = 16 cm and CD = 18 cm, find the length of AB. Model Paper 2, Concise Mathematics Solutions ICSE Class 10.

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Answer

From figure,

PD = PC + CD = 16 + 18 = 34 cm.

We know that,

If two chords intersect, then the products of the measures of the segments of the chords are equal.

∴ PA × PB = PC × PD

⇒ 14 × PB = 16 × 34

⇒ PB = 16×3414\dfrac{16 \times 34}{14}

⇒ PB = 38.86 cm

From figure,

⇒ AB = PB - AP = 38.86 - 14 = 24.86 cm

Hence, AB = 24.86 cm

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