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In the given figure, find the area of the unshaded portion within the rectangle.
(Take π = 3.14)

In the figure, find the area of the unshaded portion within the rectangle. Mensuration, ML Aggarwal Understanding Mathematics Solutions ICSE Class 9.

Mensuration

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Answer

Let ABCD be a rectangle.

In the figure, find the area of the unshaded portion within the rectangle. Mensuration, ML Aggarwal Understanding Mathematics Solutions ICSE Class 9.

From figure,

AB = CD = 6 cm and,

AD = BC = 15 cm.

Area of rectangle = l × b = AD × AB = 15 × 6 = 90 cm2.

Area of shaded portion = π(3)2 + π(3)2 + π322\dfrac{π3^2}{2}

=π(9+9+92)=452π=22.5×3.14=70.65 cm2.= π\Big(9 + 9 + \dfrac{9}{2}\Big) \\[1em] = \dfrac{45}{2}π \\[1em] = 22.5 \times 3.14 \\[1em] = 70.65 \text{ cm}^2.

Area of unshaded region = Area of rectangle - Area of shaded region

= 90 - 70.65 = 19.35 cm2.

Hence, area of unshaded region = 19.35 cm2.

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