In the given figure, . Find AB if DC = 24 cm.

Mathematics

In the given figure, $\dfrac{OA}{OC} = \dfrac{OB}{OD} = \dfrac{2}{5}$ . Find AB if DC = 24 cm.

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Answer

Since,

$\dfrac{OA}{OC} = \dfrac{OB}{OD}$ (Given)

∠AOB = ∠COD (Vertically opposite angles are equal).

∴ △AOB ~ △COD

Since, ratio of corresponding sides of similar triangles are proportional.

$\Rightarrow \dfrac{AB}{CD} = \dfrac{OB}{OD} \\[1em] \Rightarrow \dfrac{AB}{24} = \dfrac{2}{5} \\[1em] \Rightarrow AB = \dfrac{2}{5} \times 24 = \dfrac{48}{5} = 9.6 \text{ cm}.$

Hence, AB = 9.6 cm

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Class-interval	Frequency
0-30	22
30-60	30
60-90	40
90-120	36
120-150	28
150-180	20

Marks	No. of students
20-29	7
30-39	11
40-49	20
50-59	46
60-69	57
70-79	37
80-89	15
90-99	7

Mathematics

In the given figure, $\dfrac{OA}{OC} = \dfrac{OB}{OD} = \dfrac{2}{5}$ . Find AB if DC = 24 cm.

Similarity

Answer

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Draw a cumulative frequency curve and find :
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Mathematics

In the given figure, OAOC=OBOD=25\dfrac{OA}{OC} = \dfrac{OB}{OD} = \dfrac{2}{5}OCOA​=ODOB​=52​. Find AB if DC = 24 cm.

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The marks of 200 students are as given below :MarksNo. of students20-29730-391140-492050-594660-695770-793780-891590-997Draw a cumulative frequency curve and find :(i) median marks(ii) if 80% of the students passed, find the passing marks.

In the given figure, $\dfrac{OA}{OC} = \dfrac{OB}{OD} = \dfrac{2}{5}$ . Find AB if DC = 24 cm.

Using assumed mean method, calculate the mean.
Class-interval Frequency
0-30 22
30-60 30
60-90 40
90-120 36
120-150 28
150-180 20

Find the set of values of x satisfying 7x + 3 ≥ 3x - 5 and $\dfrac{x}{4} - 5 \le \dfrac{5}{4} - x, x$ ∈ N.

The marks of 200 students are as given below :
Marks No. of students
20-29 7
30-39 11
40-49 20
50-59 46
60-69 57
70-79 37
80-89 15
90-99 7
Draw a cumulative frequency curve and find :
(i) median marks
(ii) if 80% of the students passed, find the passing marks.