Mathematics
In the given figure, AOC is a diameter and AC is parallel to ED. If ∠CBE = 64°, calculate ∠DEC.
Circles
5 Likes
Answer
Join AB.
∠ABC = 90° [As angle in a semi-circle is a right angle.]
From figure,
∠ABE = ∠ABC - ∠CBE = 90° - 64° = 26°.
As angles in same segment are equal.
∠ACE = ∠ABE = 26°.
Given,
AC || ED
∴ ∠DEC = ∠ACE = 26° [Alternate angles are equal]
Hence, ∠DEC = 26°.
Answered By
3 Likes
Related Questions
In the given figure, AC is the diameter of the circle with center O. CD and BE are parallel. Angle ∠AOB = 80° and ∠ACE = 10°. Calculate :
(i) Angle BEC,
(ii) Angle BCD,
(iii) Angle CED.
Use the given figure to find :
(i) ∠BAD
(ii) ∠DQB.
In the given figure, AE is the diameter of the circle. Write down the numerical value of ∠ABC + ∠CDE. Give reasons for your answer.
In the given figure, PQ is a diameter. Chord SR is parallel to PQ. Given that ∠PQR = 58°, Calculate :
(i) ∠RPQ
(ii) ∠STP.
