Mathematics
In the figure (ii) given below, O is the center of the circle. ∠AOE = 150°, ∠DAO = 51°. Calculate the sizes of ∠BEC and ∠EBC.
Circles
42 Likes
Answer
From figure,
∠DAB = ∠DAO = 51°.
ABED is a cyclic quadrilateral as all vertices lie on the circumference of the circle.
∠BEC = ∠DAB = 51° (∵ exterior angle of a cyclic quadrilateral is equal to the opposite interior angle.)
Reflex ∠AOE = 360° - ∠AOE = 360° - 150° = 210°.
Arc AE subtends ∠ADE at point D and Reflex ∠AOE at center.
Reflex ∠AOE = 2∠ADE (∵ angle subtended by an arc at center is double the angle subtended at any other point of the circle.)
210° = 2∠ADE
∠ADE =
∠ADE = 105°.
∠EBC = ∠ADE = 105° (∵ exterior angle of a cyclic quadrilateral is equal to the opposite interior angle.)
Hence, ∠BEC = 51° and ∠EBC = 105°.
Answered By
27 Likes
Related Questions
In the figure (ii) given below, AB is parallel to DC, ∠BCE = 80° and ∠BAC = 25°. Find :
(i) ∠CAD
(ii) ∠CBD
(iii) ∠ADC
In the figure (i) given below, ABCD is a cyclic quadrilateral. If ∠ADC = 80° and ∠ACD = 52°, find the values of ∠ABC and ∠CBD.
In the figure (i) given below, ABCD is a parallelogram. A circle passes through A and D and cuts AB at E and DC at F. Given that ∠BEF = 80°, find ∠ABC.
In the figure (ii) given below, ABCD is a cyclic trapezium in which AD is parallel to BC and ∠B = 70°, find
(i) ∠BAD
(ii) ∠BCD