Mathematics
In the figure (ii) given below, ∠ADC = ∠BAC. Prove that CA2 = DC × BC.
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Answer
In △ABC and △ADC
∠C = ∠C (Common angle for both triangle)
∠BAC = ∠ADC (Given)
Then, by AA rule of similarity, △BAC ~ △ADC.
So,
Hence proved.
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