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Mathematics

In the figure (i) given below, ∠B < ∠A and ∠C < ∠D. Show that AD < BC.

In the figure (i) given below, ∠B < ∠A and ∠C < ∠D. Show that AD < BC. Triangles, ML Aggarwal Understanding Mathematics Solutions ICSE Class 9.

Triangles

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Answer

Given,

∠B < ∠A

∴ AO < BO (As side opposite to smaller angle is smaller.) ……(i)

∠C < ∠D

∴ OD < OC (As side opposite to smaller angle is smaller.) …….(ii)

From (i) and (ii) it can be concluded,

⇒ AO + OD < BO + OC

⇒ AD < BC.

Hence, proved that AD < BC.

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