Mathematics
In the figure (i) given below, ∠B < ∠A and ∠C < ∠D. Show that AD < BC.
Triangles
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Answer
Given,
∠B < ∠A
∴ AO < BO (As side opposite to smaller angle is smaller.) ……(i)
∠C < ∠D
∴ OD < OC (As side opposite to smaller angle is smaller.) …….(ii)
From (i) and (ii) it can be concluded,
⇒ AO + OD < BO + OC
⇒ AD < BC.
Hence, proved that AD < BC.
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