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In the figure (i) given below, AB is a diameter of the circle. If ∠ADC = 120°, find ∠CAB.

In the figure (i) given below, AB is a diameter of the circle. If ∠ADC = 120°, find ∠CAB. Circles, ML Aggarwal Understanding Mathematics Solutions ICSE Class 10.

Circles

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Answer

Join CB as shown in the figure below:

In the figure (i) given below, AB is a diameter of the circle. If ∠ADC = 120°, find ∠CAB. Circles, ML Aggarwal Understanding Mathematics Solutions ICSE Class 10.

So, ABCD becomes a cyclic quadrilateral.

Sum of opposite angles of cyclic quadrilateral = 180°

⇒ ∠CBA + ∠ADC = 180°
⇒ ∠CBA + 120° = 180°
⇒ ∠CBA = 180° - 120°
⇒ ∠CBA = 60°.

Join AC.

In △ABC

∠ACB = 90° (∵ angle in semicircle is equal to 90°.)

Sum of angles of triangle = 180°

⇒ ∠CAB + ∠ACB + ∠CBA = 180°
⇒ ∠CAB + 90° + 60° = 180°
⇒ ∠CAB + 150° = 180°
⇒ ∠CAB = 180° - 150°
⇒ ∠CAB = 30°.

Hence, the value of ∠CAB = 30°.

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