Mathematics
In the figure, given below, CP bisects angle ACB. Show that DP bisects angle ADB.
Circles
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Answer
Since, CP is the bisector of ∠ACB,
∴ ∠ACP = ∠BCP ………(1)
We know that,
Angles in same segment are equal.
∴ ∠ACP = ∠ADP ……….(2)
∠BCP = ∠BDP ………..(3)
From (1) and (2) we get,
∠BCP = ∠ADP ………..(4)
From (3) and (4) we get,
∠ADP = ∠BDP.
∴ DP is the bisector of ∠ADB.
Hence, proved that DP is the bisector of ∠ADB.
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