Mathematics
In the figure, given below, ∠ABC is equal to :
105°
75°
90°
45°
Circles
3 Likes
Answer
We know that,
Sum of co-interior angles in a trapezium is equal to 180°.
⇒ ∠A + ∠D = 180°
⇒ 105° + ∠D = 180°
⇒ ∠D = 180° - 105° = 75°
We know that,
The opposite angles of a cyclic quadrilateral is 180°.
In cyclic quadrilateral ABCD,
⇒ ∠D + ∠B = 180°
⇒ 75° + ∠B = 180°
⇒ ∠B = 180° - 75° = 105°.
Hence, Option 1 is the correct option.
Answered By
1 Like
Related Questions
In the given figure, O is the center of the circle. ∠OAB and ∠OCB are 30° and 40° respectively. ∠AOC is equal to :
70°
80°
150°
140°
In the figure, given below, ABCD is a cyclic quadrilateral in which ∠BAD = 75°; ∠ABD = 58° and ∠ADC = 77°. Find :
(i) ∠BDC,
(ii) ∠BCD,
(iii) ∠BCA.
In the given figure APB and CQD are two straight lines, then :
AB || CD
AC || PQ
PQ || BD
AC || BD
In the given figure, O is the centre of the circle. If ∠AOB = 140° and ∠OAC = 50°; find :
(i) ∠ACB,
(ii) ∠OBC,
(iii) ∠OAB,
(iv) ∠CBA.