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In the figure (2) given below, ∆ABC is right-angled at B. If AB = y units, BC = 3 units and CA = 5 units, find

(i) sin x°

(ii) y.

In the figure, ∆ABC is right-angled at B. If AB = y units, BC = 3 units and CA = 5 units, find (i) sin x° (ii) y. Trigonometrical Ratios, ML Aggarwal Understanding Mathematics Solutions ICSE Class 9.

Trigonometrical Ratios

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Answer

(i) By formula,

sin x° = PerpendicularHypotenuse\dfrac{\text{Perpendicular}}{\text{Hypotenuse}}

= BCAC=35\dfrac{BC}{AC} = \dfrac{3}{5}.

Hence, sin x° = 35\dfrac{3}{5}.

(ii) In right-angled ∆ABC

Using pythagoras theorem

⇒ AC2 = BC2 + AB2

⇒ AB2 = AC2 - BC2

⇒ y2 = 52 - 32

⇒ y2 = 25 - 9

⇒ y2 = 16

⇒ y = 16\sqrt{16}

⇒ y = 4.

Hence, y = 4 units.

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