KnowledgeBoat Logo

Mathematics

In the extract of Survey of India map G43S7, prepared on a scale of 2 cm to 1 km, a child finds the length of the cart track between two settlements is 7.6 cm. Find :

(a) the actual length of the cart track on the ground.

(b) actual area of a grid square, if each has an area of 4 cm2.

Similarity

6 Likes

Answer

Scale factor (k) = 2 cm to 1 km or 2 cm to 100000 cm = 2100000=150000\dfrac{2}{100000} = \dfrac{1}{50000}

(a) Length of cart track on map = k × Length of cart track on ground

7.6=1500007.6 = \dfrac{1}{50000} × Length of cart track on ground

Length of cart track on ground = 7.6 × 50000 = 380000 cm = 380000100000\dfrac{380000}{100000} = 3.8 km

Hence, length of actual cart track on ground = 3.8 km

(b) Area of model grid square = k2 × Area of actual grid square

⇒ 4 = (150000)2\Big(\dfrac{1}{50000}\Big)^2 × Area of actual grid square

⇒ 4 = (125×108)\Big(\dfrac{1}{25 \times 10^8}\Big) × Area of actual grid square

⇒ Area of actual grid square = 4×25×1084 \times 25 \times 10^8

⇒ Area of actual grid square = 100 × 108 = 102 × 108 = 1010 cm2

= 10101010\dfrac{10^{10}}{10^{10}} km2 = 1 km2.

Hence, actual area of a grid square = 1 km2.

Answered By

5 Likes


Related Questions