Chemistry
In the electrolytic reduction of pure alumina to pure aluminium by Hall Herault's process, give the electrolytic reactions involved in the same, resulting in formation of aluminium at the cathode.
Metallurgy
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Answer
In the electrolytic reduction of pure alumina to pure aluminium by Hall Herault's process, the constitutents of electrolyte are cryolite (Na3AlF6) and fluorspar (CaF2) and alumina (Al2O3)
The electrolytic reactions are as follows :
Cryolite : Na3AlF6 ⇌ 3Na1+ + Al3+ + 6F1-
Fluorspar : CaF2 ⇌ Ca2+ + 2F1-
Alumina : Al2O3 ⇌ 2Al3+ + 3O2-
At cathode : 2Al3+ + 6e- ⟶ 2Al
At anode : 3O2- - 6e- ⟶ 3[O] ⟶ 3O2
Al3+ are discharged in preference to Na1+ and Ca2+ ions due to it's lower position in the electrochemical series.
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Related Questions
Give reasons for the following:
Coke is not preferred as a reducing agent in the reduction of the oxide of mercury to it's metal, but is preferred in the reduction of the oxide of zinc to it's metal.In the extraction of aluminium from bauxite, the first step is the dressing of the ore by Baeyer's process. Give balanced equations for the conversion of impure bauxite to pure alumina using a concentrated solution of NaOH.
State the function of (i) Sodium hydroxide (ii) Cryolite (iii) Fluorspar in the metallurgy of aluminium in Hall Herault's process.
Give reasons for the following pertaining to Hall Herault's process.
(i) The fusion temperature of the electrolyte has to be lowered before conducting the electrolytic reduction.
(ii) The constituents of the electrolyte in addition to one part of fused alumina contains three parts of cryolite and one part of fluorspar.
(iii) A layer of powdered coke sprinkled over the electrolytic mixture, protects the carbon electrodes.
(iv) It is preferred to use a number of graphite electrodes as anode, instead of a single graphite electrode.