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Chemistry

In the electrolytic reduction of pure alumina to pure aluminium by Hall Herault's process, give the electrolytic reactions involved in the same, resulting in formation of aluminium at the cathode.

Metallurgy

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Answer

In the electrolytic reduction of pure alumina to pure aluminium by Hall Herault's process, the constitutents of electrolyte are cryolite (Na3AlF6) and fluorspar (CaF2) and alumina (Al2O3)

The electrolytic reactions are as follows :

Cryolite : Na3AlF6 ⇌ 3Na1+ + Al3+ + 6F1-

Fluorspar : CaF2 ⇌ Ca2+ + 2F1-

Alumina : Al2O3 ⇌ 2Al3+ + 3O2-

At cathode : 2Al3+ + 6e- ⟶ 2Al

At anode : 3O2- - 6e- ⟶ 3[O] ⟶ 3O2

Al3+ are discharged in preference to Na1+ and Ca2+ ions due to it's lower position in the electrochemical series.

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