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State the function of (i) Sodium hydroxide (ii) Cryolite (iii) Fluorspar in the metallurgy of aluminium in Hall Herault's process.

Metallurgy

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Answer

(i) Function of Sodium hydroxide — Sodium hydroxide is added to bauxite ore during purification of bauxite. Bauxite is reacted with a conc. solution of Sodium hydroxide under pressure for 2 hours as a first step in obtaining Al2O3.

The impurities present in bauxite mainly Fe2O3 and SiO2 remain unaffected with conc. NaOH as impurities are not amphoteric.

Bauxite, being amphoteric reacts with the base forming sodium salt [sodium aluminate] and water. Hence, impurities are separated out.

Al2O3.2H2[Impure bauxite]Amphoteric oxide+2NaOH [conc. soln]Base150200°C2NaAlO2[sodium aluminate]Salt+3H2OWater\underset{\text{Amphoteric oxide}}{\underset{\text{[Impure bauxite]}}{\text{Al}2\text{O}3.2\text{H}2\text{O }}} + \underset{\text{Base}}{\underset{\text{[conc. soln]}}{2\text{NaOH }}} \xrightarrow{150 - 200 \degree\text{C}} \underset{\text{Salt}}{\underset{\text{[sodium aluminate]}}{2\text{NaAlO}2}} + \underset{\text{Water}}{ \text{3H}_2\text{O}}

(ii) Addition of Cryolite & Fluorspar

  1. Lowers the fusion point of the mixture i.e., mixture fuses around 950°C instead of 2050°C.
  2. Enhances the mobility of the fused mixture by acting as a solvent for the electrolytic mixture.
  3. Addition of Cryolite enhances the conductivity of the mixture since, pure alumina is almost a non-conductor of electricity.

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