In the adjoining figure, not drawn to the scale, AB is a tower and two objects C and D are located on the ground, on the same side of AB. When observed from the top A of the tower, their angles of depression are 45° and 60°. Find the distance between the two objects, if the height of the tower is 300 m. Give your answer to the nearest meter.

From figure, ∠ACB = ∠EAC = 45° (Alternate angles are equal) ∠ADB = ∠EAD = 60° (Alternate angles are equal) Considering right angled △ABC, we get Considering right angled △ADB, we get Distance between two objects (CD) = CB - DB = 300 - 173.2 = 126.8. Rounding off to nearest meter CD = 127 m. Hence, the distance between two objects = 127 meters.

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The horizontal distance between two towers is 140 m. The angle of elevation of the top of the first tower, when seen from the top of the second tower is 30°. If the height of the second tower is 60 m, find the height of the first tower.

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As observed from the top of a 80 m tall light house, the angles of depression of two ships on the same side of the light house in horizontal line with its base are 30° and 40° respectively. Find the distance between the two ships. Give your answer correct to nearest meter.

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Mathematics

Heights & Distances

Related Questions

The horizontal distance between two towers is 140 m. The angle of elevation of the top of the first tower, when seen from the top of the second tower is 30°. If the height of the second tower is 60 m, find the height of the first tower.

As observed from the top of a 80 m tall light house, the angles of depression of two ships on the same side of the light house in horizontal line with its base are 30° and 40° respectively. Find the distance between the two ships. Give your answer correct to nearest meter.