Mathematics
In the adjoining figure, DE || CA and D is a point on BD such that BD : DC = 2 : 1. The ratio of area of △ABC to area of △BDE is
4 : 1
9 : 1
9 : 4
3 : 2
Related Questions
The areas of two similar triangles are 81 cm2 and 49 cm2 respectively. If an altitude of the smaller triangle is 3.5 cm, then the corresponding altitude of the bigger triangle is
9 cm
7 cm
6 cm
4.5 cm
If △ABC ~ △PQR, area of △ABC = 81 cm2, area of △PQR = 144 cm2 and QR = 6 cm, then length of BC is
4 cm
4.5 cm
9 cm
12 cm
If ABC and BDE are two equilateral triangles such that D is mid-point of BC, then the ratio of the areas of triangles ABC and BDE is
2 : 1
1 : 2
1 : 4
4 : 1