Mathematics
In the adjoining figure, BA ⊥ AC, DE ⊥ DF such that BA = DE and BF = EC. Show that △ABC ≅ △DEF.
Triangles
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Answer
In △ABC and △DEF,
BF = EC (Given)
⇒ BF + FC = EC + FC
∴ BC = FE.
BA = DE (Given)
∠BAC = ∠EDF (Both are equal to 90°)
∴ △ABC ≅ △DEF (By RHS axiom)
Hence, proved that △ABC ≅ △DEF.
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