Mathematics
In the adjoining figure, AD and BE are medians of △ABC. If DF || BE, prove that CF =
Related Questions
In the adjoining figure, ABCD is a parallelogram. E and F are mid-points of the sides AB and CD respectively. The straight lines AF and BF meet the straight lines ED and EC in points G and H respectively. Prove that
(i) △HEB ≅ △HCF
(ii) GEHF is a parallelogram.
Show that the quadrilateral formed by joining the mid-points of the adjacent sides of a square, is also a square.
ABC is an isosceles triangle with AB = AC. D, E and F are mid-points of the sides BC, AB and AC respectively. Prove that line segment AD is perpendicular to EF and is bisected by it.