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Mathematics

In an election between two candidates, one candidate secured 47% of votes polled and lost the election by 12,366 votes. Find the total votes polled and the votes secured by the winning candidate.

Percent & Percentage

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Answer

Given:

Winner lost by = 12,336 votes

Votes secured by one candidate = 47 %

Votes secured by other candidate = (100 % - 47 %) = 53 %

Let the total number of votes be xx.

Difference in votes of two candidates = 12,336

⇒ 53% of xx - 47% of xx = 12,336

⇒ (53% - 47%) of xx = 12,336

⇒ 6% of xx = 12,336

6100×x=12,336\dfrac{6}{100} \times x = 12,336

x=12,336×1006x = \dfrac{12,336 \times 100}{6}

x=12,33,6006x = \dfrac{12,33,600}{6}

x=2,06,100x = 2,06,100

Votes secured by candidates who won the election = 53 % of total votes

= 53100×2,06,100\dfrac{53}{100} \times 2,06,100

= 1,09,23,300100\dfrac{1,09,23,300}{100}

= 1,09,233

The total number of votes = 2,06,100 and votes secured by the winning candidates = 1,09,233.

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