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Mathematics

In an election between two candidates, one candidate secured 58% of the votes polled and won the election by 18,336 votes. Find the total number of votes polled and the votes secured by each candidate.

Percent & Percentage

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Answer

Given:

Winner won by = 18,336 votes

Votes secured by one candidate = 58 %

Votes secured by other candidate = (100 % - 58 %) = 42 %

Let the total number of votes be xx.

Difference in votes of two candidates = 18,336

⇒ 58% of xx - 42% of xx = 18,336

⇒ (58% - 42%) of xx = 18,336

⇒ 16% of xx = 18,336

16100×x=18,336\dfrac{16}{100} \times x = 18,336

x=18,336×10016x = \dfrac{18,336 \times 100}{16}

x=18,33,60016x = \dfrac{18,33,600}{16}

x=1,14,600x = 1,14,600

Votes secured by one candidate = 58 % of total votes

= 58100×1,14,600\dfrac{58}{100} \times 1,14,600

= 66,46,800100\dfrac{66,46,800}{100}

= 66,468

Votes secured by other candidate = 42 % of total votes

= 42100×1,14,600\dfrac{42}{100} \times 1,14,600

= 48,13,200100\dfrac{48,13,200}{100}

= 48,132

The total number of votes = 1,14,600, votes secured by one candidates = 66,468 and votes secured by other candidates = 48,132.

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