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Mathematics

In a class of 90 students, the marks obtained in a weekly test were as under :

MarksNo. of students
16 - 204
21 - 2512
26 - 3018
31 - 3526
36 - 4014
41 - 4510
46 - 506

Draw a frequency polygon for the above data.

Statistics

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Answer

The following frequency distribution is discontinuous, to convert it into continuous frequency distribution,

Adjustment factor = (Lower limit of one class - Upper limit of previous class) / 2

= 21202=12\dfrac{21 - 20}{2} = \dfrac{1}{2}

= 0.5

Subtract the adjustment factor (0.5) from all the lower limits and add the adjustment factor (0.5) to all the upper limits.

Continuous frequency distribution for given data is :

Classes before adjustmentClasses after adjustmentClass markFrequency
16 - 2015.5 - 20.5184
21 - 2520.5 - 25.52312
26 - 3025.5 - 30.52818
31 - 3530.5 - 35.53326
36 - 4035.5 - 40.53814
41 - 4540.5 - 45.54310
46 - 5045.5 - 50.5486

Steps to draw frequency polygon :

  1. Since, the scale on x-axis starts at 10.5, a kink is shown near the origin on x-axis to indicate that the graph is drawn to scale beginning at 10.5.

  2. Take 1 cm along x-axis = 5 marks.

  3. Take 1 cm along y-axis = 5 students.

  4. Find the mid-points of class-intervals.

  5. Find points corresponding to given frequencies of classes and the mid-points of class-intervals, and plot them.

  6. Join consecutive points by line segments.

  7. Join first end point with mid-point of class 10.5 - 15.5 with zero frequency and join the other end with mid-point of class 50.5 - 55.5 with zero frequency.

The required frequency polygon is shown alongside.

In a class of 90 students, the marks obtained in a weekly test were as under. Statistics, ML Aggarwal Understanding Mathematics Solutions ICSE Class 9.

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