Find a relation between x and y such that point (x, y) is equidistant from the points (7, 1) and (3, 5).

Using distance formula, show that (3, 3) is the center of the circle passing through the points (6, 2), (0, 4) and (4, 6).

The x-coordinate of a point P is twice its y-coordinate. If P is equidistant from the points Q(2, -5) and R(-3, 6), then find the coordinates of P.

If a point A(0, 2) is equidistant from the points B(3, p) and C(p, 5), then find the value of p.