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Mathematics

If the mean of the following observations is 54, find the value of p.

ClassFrequency
0 - 207
20 - 40p
40 - 6010
60 - 809
80 - 10013

Measures of Central Tendency

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Answer

By formula,

Class mark = Upper limit + Lower limit2\dfrac{\text{Upper limit + Lower limit}}{2}

ClassClass mark (x)Frequency (f)fx
0 - 2010770
20 - 4030p30p
40 - 605010500
60 - 80709630
80 - 10090131170
TotalΣf = 39 + p2370 + 30p

By formula,

Mean = ΣfxΣf\dfrac{Σfx}{Σf}

⇒ 54 = 2370+30p39+p\dfrac{2370 + 30p}{39 + p}

⇒ 54(39 + p) = 2370 + 30p

⇒ 2106 + 54p = 2370 + 30p

⇒ 54p - 30p = 2370 - 2106

⇒ 24p = 264

⇒ p = 26424\dfrac{264}{24}

⇒ p = 11.

Hence, p = 11.

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