If the common difference of the A.P. is 5, then a 18 - a 13 is 1. 5 2. 20 3. 25 4. 30

Given d = 5, We know that a n = a + (n - 1)d ∴ a 18 = a + (18 - 1) × 5 = a + 17 × 5 = a + 85. a 13 = a + (13 - 1) × 5 = a + 12 × 5 = a + 60. ∴ a 18 - a 13 = a + 85 - (a + 60) = a - a + 85 - 60 = 25. Hence, Option 3 is the correct option.

Mathematics

If the common difference of the A.P. is 5, then a₁₈ - a₁₃ is
5
20
25
30

AP GP

4 Likes

Answer

Given d = 5,

We know that

a_n = a + (n - 1)d
∴ a₁₈ = a + (18 - 1) × 5 = a + 17 × 5 = a + 85.
a₁₃ = a + (13 - 1) × 5 = a + 12 × 5 = a + 60.

∴ a₁₈ - a₁₃ = a + 85 - (a + 60) = a - a + 85 - 60 = 25.

Hence, Option 3 is the correct option.

Answered By

3 Likes

Mathematics

If the common difference of the A.P. is 5, then a₁₈ - a₁₃ is
5
20
25
30

AP GP

Answer

Related Questions

The 11th term of the A.P. $-3, -\dfrac{1}{2}, 2, …$ is
28
22
-38
$-48\dfrac{1}{2}$

The 15th term from the last of the A.P. 7, 10, 13, … , 130 is
49
85
88
110

In an A.P., if a₁₈ - a₁₄ = 32 then the common difference is
8
-8
-4
4

In an A.P., if d = -4, n = 7, a_n = 4, then a is
6
7
20
28

Mathematics

If the common difference of the A.P. is 5, then a18 - a13 is5202530

AP GP

Answer

Related Questions

The 11th term of the A.P. −3,−12,2,...-3, -\dfrac{1}{2}, 2, …−3,−21​,2,… is2822-38−4812-48\dfrac{1}{2}−4821​

The 15th term from the last of the A.P. 7, 10, 13, … , 130 is498588110

In an A.P., if a18 - a14 = 32 then the common difference is8-8-44

In an A.P., if d = -4, n = 7, an = 4, then a is672028

If the common difference of the A.P. is 5, then a₁₈ - a₁₃ is
5
20
25
30

The 11th term of the A.P. $-3, -\dfrac{1}{2}, 2, …$ is
28
22
-38
$-48\dfrac{1}{2}$

The 15th term from the last of the A.P. 7, 10, 13, … , 130 is
49
85
88
110

In an A.P., if a₁₈ - a₁₄ = 32 then the common difference is
8
-8
-4
4

In an A.P., if d = -4, n = 7, a_n = 4, then a is
6
7
20
28