If P(4, 3) is mid-point of line segment AB, then

1. A = (6, 0), B = (0, 8)

2. A = (8, 6), B = (8, 0)

3. A = (6, 8), B = (0, 6)

4. A = (8, 0) and B = (0, 6)

From figure,

A lies on x-axis and B lies on y-axis.

Let co-ordinates of A be (x, 0) and B be (0, y).

Given,

P(4, 3) is mid-point of line segment AB.

By mid-point formula,

Mid-point = $\Big(\dfrac{x$1 + x2}{2}, \dfrac{y1 + y2}{2}\Big)

Substituting values we get :

$\Rightarrow (4, 3) = \Big(\dfrac{x + 0}{2}, \dfrac{0 + y}{2}\Big) \\[1em] \Rightarrow (4, 3) = \Big(\dfrac{x}{2}, \dfrac{y}{2}\Big) \\[1em] \Rightarrow \dfrac{x}{2} = 4 \text{ and } \dfrac{y}{2} = 3 \\[1em] \Rightarrow x = 8 \text{ and } y = 6.$

A = (x, 0) = (8, 0),

B = (0, y) = (0, 6).

Hence, Option 4 is the correct option.