If △ABC ~ △PQR, BC = 8 cm and QR = 6 cm, then the ratio of the areas of △ABC and △PQR is 1. 8 : 6 2. 3 : 4 3. 9 : 16 4. 16 : 9

Since triangles are similar. We know that, the ratio of the areas of two similar triangles is equal to the ratio of the square of their corresponding sides. Hence, Option 4 is the correct option.

If △ABC ~ △PQR, area of △ABC = 81 cm², area of △PQR = 144 cm² and QR = 6 cm, then length of BC is
4 cm
4.5 cm
9 cm
12 cm

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It is given that △ABC ~ △PQR with $\dfrac{BC}{QR} = \dfrac{1}{3}$ , then $\dfrac{\text{area of △PQR}}{\text{area of △ABC}}$ is equal to
9
3
$\dfrac{1}{3}$
$\dfrac{1}{9}$

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If the areas of two similar triangles are in the ratio 4 : 9, then their corresponding sides are in the ratio
9 : 4
3 : 2
2 : 3
16 : 81

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If △ABC ~ △QRP, $\dfrac{\text{area of △ABC}}{\text{area of △PQR}} = \dfrac{9}{4}$ , AB = 18 cm and BC = 15 cm, then the length of PR is equal to
10 cm
12 cm
$\dfrac{20}{3}$ cm
8 cm

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Mathematics

If △ABC ~ △PQR, BC = 8 cm and QR = 6 cm, then the ratio of the areas of △ABC and △PQR is
8 : 6
3 : 4
9 : 16
16 : 9

Similarity

Answer

Related Questions

If △ABC ~ △PQR, area of △ABC = 81 cm², area of △PQR = 144 cm² and QR = 6 cm, then length of BC is
4 cm
4.5 cm
9 cm
12 cm

It is given that △ABC ~ △PQR with $\dfrac{BC}{QR} = \dfrac{1}{3}$ , then $\dfrac{\text{area of △PQR}}{\text{area of △ABC}}$ is equal to
9
3
$\dfrac{1}{3}$
$\dfrac{1}{9}$

If the areas of two similar triangles are in the ratio 4 : 9, then their corresponding sides are in the ratio
9 : 4
3 : 2
2 : 3
16 : 81

If △ABC ~ △QRP, $\dfrac{\text{area of △ABC}}{\text{area of △PQR}} = \dfrac{9}{4}$ , AB = 18 cm and BC = 15 cm, then the length of PR is equal to
10 cm
12 cm
$\dfrac{20}{3}$ cm
8 cm

Mathematics

If △ABC ~ △PQR, BC = 8 cm and QR = 6 cm, then the ratio of the areas of △ABC and △PQR is8 : 63 : 49 : 1616 : 9

Similarity

Answer

Related Questions

If △ABC ~ △PQR, area of △ABC = 81 cm2, area of △PQR = 144 cm2 and QR = 6 cm, then length of BC is4 cm4.5 cm9 cm12 cm

It is given that △ABC ~ △PQR with BCQR=13\dfrac{BC}{QR} = \dfrac{1}{3}QRBC​=31​, then area of △PQRarea of △ABC\dfrac{\text{area of △PQR}}{\text{area of △ABC}}area of △ABCarea of △PQR​ is equal to9313\dfrac{1}{3}31​19\dfrac{1}{9}91​

If the areas of two similar triangles are in the ratio 4 : 9, then their corresponding sides are in the ratio9 : 43 : 22 : 316 : 81

If △ABC ~ △QRP, area of △ABCarea of △PQR=94\dfrac{\text{area of △ABC}}{\text{area of △PQR}} = \dfrac{9}{4}area of △PQRarea of △ABC​=49​, AB = 18 cm and BC = 15 cm, then the length of PR is equal to10 cm12 cm203\dfrac{20}{3}320​ cm8 cm

If △ABC ~ △PQR, BC = 8 cm and QR = 6 cm, then the ratio of the areas of △ABC and △PQR is
8 : 6
3 : 4
9 : 16
16 : 9

If △ABC ~ △PQR, area of △ABC = 81 cm², area of △PQR = 144 cm² and QR = 6 cm, then length of BC is
4 cm
4.5 cm
9 cm
12 cm

It is given that △ABC ~ △PQR with $\dfrac{BC}{QR} = \dfrac{1}{3}$ , then $\dfrac{\text{area of △PQR}}{\text{area of △ABC}}$ is equal to
9
3
$\dfrac{1}{3}$
$\dfrac{1}{9}$

If the areas of two similar triangles are in the ratio 4 : 9, then their corresponding sides are in the ratio
9 : 4
3 : 2
2 : 3
16 : 81

If △ABC ~ △QRP, $\dfrac{\text{area of △ABC}}{\text{area of △PQR}} = \dfrac{9}{4}$ , AB = 18 cm and BC = 15 cm, then the length of PR is equal to
10 cm
12 cm
$\dfrac{20}{3}$ cm
8 cm