Chemistry

Given that the relative molecular mass of copper oxide is 80, what volume of ammonia (measured at STP) is required to completely reduce 120 g of copper oxide? The equation for the reaction is:
3CuO + 2NH₃ ⟶ 3Cu + 3H₂O + N₂

Mole Concept

10 Likes

Answer

$\begin{matrix} 3\text{CuO} & + & 2\text{NH}_3 \ 3\text{ mol.} & & 2 \text{ mol.} \ = 3 \times 80 \text{ g.} & & = 2 \times 22.4 \text{ lit.} \ = 240 \text{ g.} & & = 44.8\text{ lit.} \ \end{matrix}$

$\longrightarrow 3\text{Cu} + 3\text{H}$

240 g of CuO is reduced by 44.8 lit of NH₃

∴ 120 g of CuO is reduced by $\dfrac{44.8}{240}$ x 120 = 22.4 lit.

Hence, 22.4 lit of NH₃ is required

Answered By

2 Likes

Related Questions

The equations given below relate to the manufacture of sodium carbonate [Mol. wt. of Na₂CO₃ = 106]
(i) NaCl + NH₃ + CO₂ + H₂O ⟶ NaHCO₃ + NH₄Cl
(ii) 2NaHCO₃ ⟶ Na₂CO₃ + H₂O + CO₂
Equations (1) and (2) are based on the production of 21.2 g. of sodium carbonate.
(a) What mass of sodium hydrogen carbonate must be heated to give 21.2 g. of sodium carbonate
(b) To produce the mass of sodium hydrogen carbonate calculated in (a), what volume of carbon dioxide, measured at s.t.p., would be required.
View Answer