Mathematics
In the given diagram, ∆ABC ∼ ∆PQR. If AD and PS are bisectors of ∠BAC and ∠QPR respectively then:
∆ABC ∼ ∆PQS
∆ABD ∼ ∆PQS
∆ABD ∼ ∆PSR
∆ABC ∼ ∆PSR

Similarity
ICSE 2024
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Answer
Given,
∆ABC ∼ ∆PQR
∴ ∠A = ∠P
⇒
⇒ ∠BAD = ∠QPS
∠B = ∠Q [∵ ∆ABC ∼ ∆PQR]
In ∆ABD ∼ ∆PQS,
⇒ ∠BAD = ∠QPS
⇒ ∠B = ∠Q
∴ ∆ABD ∼ ∆PQS (By A.A. axiom)
Hence, Option 2 is the correct option.
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