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Chemistry

Give three tests for hydrochloric acid. Convert silver nitrate to a soluble salt of silver using hydrochloric acid and an alkali.

Hydrogen Chloride

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Answer

(i) When glass rod dipped in ammonia solution (NH4OH) is brought near vapours of hydrochloric acid, dense white fumes of ammonium chloride are formed.

NH3[aq.]+HCl[vapour]NH4Cl[dense white fumes]\underset{\text{[aq.]}}{\text{NH}3} + \underset{\text{[vapour]}}{\text{HCl}} \longrightarrow \underset{\text{[dense white fumes]}}{\text{NH}4\text{Cl}}

(ii) On addition of silver nitrate soln. to dil. HCl (acidified with dil. HNO3), curdy white precipitate of silver chloride is obtained.

AgNO3 + HCl ⟶ AgCl ↓ + HNO3

(iii) On heating a mixture of manganese dioxide and conc. HCl, Greenish yellow gas (chlorine) is evolved.

MnO2 + 4HCl ⟶ MnCl2 ↓ + 2H2O + Cl2

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