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Chemistry

Give balanced equations for the conversions A, B, C, D and E given below :

  1. Conc. HCl→APbCl2←Bdil. HCl\text{Conc. HCl} \xrightarrow{\text{A}} \text{PbCl}_2 \xleftarrow{\text{B}} \text{dil. HCl}
  2. NaHCO3→CNaCl→DNaHSO4\text{NaHCO}3 \xrightarrow{\text{C}} \text{NaCl} \xrightarrow{\text{D}} \text{NaHSO}4
  3. FeCl3←E1Fe→E2FeCl2\text{FeCl}3 \xleftarrow{\text{E}1} \text{Fe} \xrightarrow{\text{E}2} \text{FeCl}2

Hydrogen Chloride

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Answer

  1. A — 4HCl(conc.)+PbO2→ΔPbCl2+2H2O+Cl24\text{HCl(conc.)} + \text{PbO}2 \xrightarrow{\Delta} \text{PbCl}2 + 2\text{H}2\text{O} + \text{Cl}2
    B — 2HCl(dil.)+Pb(NO3)2→ΔPbCl2↓+2HNO32\text{HCl(dil.)} + \text{Pb(NO}3)2 \xrightarrow{\Delta} \text{PbCl}2 \downarrow + 2\text{HNO}3
  2. C — NaHCO3 + HCl ⟶ NaCl + H2O + CO2
    D — NaCl+H2SO4→<200°CNaHSO4+HCl [g]\text{NaCl} + \text{H}2\text{SO}4 \xrightarrow{\lt 200 \degree\text{C}} \text{NaHSO}_\text{4} + \text{HCl [g]}
  3. E1 — 2Fe + 3Cl2 ⟶ 2FeCl3
    E2 — Fe + 2HCl [g] ⟶ FeCl2 + H2 [g]

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