Chemistry
Give equations for oxidation of conc. H2SO4 giving the oxidised products –
(i) Carbon dioxide
(ii) Sulphur dioxide
(iii) Phosphoric acid
(iv) Copper (II) sulphate
(v) Iodine
(vi) Sulphur
respectively
Sulphuric Acid
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Answer
(i) C + 2H2SO4 (conc.) ⟶ CO2 + 2SO2 + 2H2O
(ii) S + 2H2SO4 (conc.) ⟶ 3SO2 + 2H2O
(iii) 2P + 5H2SO4 (conc.) ⟶ 2H3PO4 + 5SO2 + 2H2O
(iv) Cu + 2H2SO4 (conc.) ⟶ CuSO4 + SO2 + 2H2O
(v) 2HI + H2SO4 (conc.) ⟶ I2 + SO2 + 2H2O
(vi) H2S + H2SO4 (conc.) ⟶ S + SO2 + 2H2O
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Related Questions
Convert dil. H2SO4 to –
(i) Hydrogen
(ii) Carbon dioxide
(iii) Sulphur dioxide
(iv) Hydrogen sulphide
(v) An acid salt
(vi) A normal salt.
Give equations for formation of two different acids from conc. H2SO4. State the property of sulphuric acid involved in the above formation.
Give a reason why concentrated and not dil H2SO4 behaves as an oxidising and dehydrating agent.
Give the equation for the reaction of conc. sulphuric acid with –
(i) glucose
(ii) sucrose
(iii) cellulose
(iv) an organic acid containing one carbon atom and two hydrogen atoms
(v) an organic acid containing two carbon and two hydrogen atoms
(vi) an alcohol
(vii) hydrated copper [II] sulphate