Mathematics

Find the total surface area of an open pipe of length 50 cm, external diameter 20 cm and internal diameter 6 cm.

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Given,

Length of the open pipe = 50 cm

External diameter = 20 cm

External radius (R) = $\dfrac{20}{2}$ = 10 cm

Internal diameter = 6 cm

Internal radius (r) = $\dfrac{6}{2}$ = 3 cm

Surface area of pipe open from both sides = 2πRh + 2πrh = 2πh(R + r)

= 2 x $\dfrac{22}{7}$ x 50 x (10 + 3)

= 4085.71 cm²

Area of upper and lower part = 2πR² - 2πr²

= 2 x $\dfrac{22}{7}$ x (10² - 3²)

= 2 x $\dfrac{22}{7}$ x 91

= 572 cm².

Total surface area = 4085.71 + 572 = 4657.71 cm².

Hence, total surface area of open pipe = 4657.71 cm².

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