Mathematics
A cylindrical container with internal radius of its base 10 cm, contains water up to a height of 7 cm. Find the area of wet surface of the cylinder.
Mensuration
23 Likes
Answer
Given,
Internal radius of the cylindrical container (r) = 10 cm
Height of water (h) = 7 cm
So, the surface area of the wet surface = 2πrh + πr2 = πr(2h + r)
= x 10 x (2 x 7 + 10)
= x 24
= 754.29 cm2.
Hence, the area of wet surface of cylinder = 754.29 cm2.
Answered By
11 Likes
Related Questions
A metal pipe has a bore (inner diameter) of 5 cm. The pipe is 5 mm thick all round. Find the weight, in kilogram, of 2 metres of the pipe if 1 cm3 of the metal weights 7.7 g.
A cylindrical container with diameter of base 42 cm contains sufficient water to submerge a rectangular solid of iron with dimensions 22 cm x 14 cm x 10.5 cm. Find the rise in the level of the water when the solid is submerged.
Find the total surface area of an open pipe of length 50 cm, external diameter 20 cm and internal diameter 6 cm.
The height and the radius of the base of a cylinder are in the ratio 3 : 1. If its volume is 1029 π cm3; find its total surface area.