Mathematics
Find the size of each lettered angle in the following figure.
Rectilinear Figures
3 Likes
Answer
As CDE is a straight line
∠ADE + ∠ADC = 180°
122° + ∠ADC = 180°
∠ADC = 180° – 122° = 58° … (i)
Internal ∠ABC = 360° – 140° = 220° … (ii)
Now, in quadrilateral ABCD we have
⇒ ∠ADC + ∠BCD + ∠BAD + ∠ABC = 360° (As sum of all angles in a quadrilateral is 360°.)
⇒ 58° + 53° + x + 220° = 360° [Using (i) and (ii)]
⇒ 331° + x = 360°
⇒ x = 360° – 331°
⇒ x = 29°
Hence, x = 29°
Answered By
3 Likes
Related Questions
Find the size of each lettered angle in the following figure.
Find the size of each lettered angle in the following figure.
Prove that the quadrilateral obtained by joining the mid-points of an isosceles trapezium is a rhombus.
In the adjoining figure, ABC is an isosceles triangle in which AB = AC. AD bisects exterior angle PAC and CD || BA. Show that
(i) ∠DAC = ∠BCA
(ii) ABCD is a parallelogram.