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Mathematics

Find the equation of the line through (1, 3) and making an intercept of 5 on the y-axis.

Straight Line Eq

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Answer

When y-intercept = 5; corresponding point on the y-axis = (0, 5).

Slope of the line through (0, 5) and (1, 3) = 3−51−0=−21=−2\dfrac{3 - 5}{1 - 0} = \dfrac{-2}{1} = -2.

By point-slope form,

⇒ y - y1 = m(x - x1)

⇒ y - 5 = -2(x - 0)

⇒ y - 5 = -2x

⇒ 2x + y = 5.

Hence, equation of line is 2x + y = 5.

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