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Chemistry

Find the empirical formula of a compound containing 17.64% hydrogen and 82.35% nitrogen.

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Answer

Element% compositionAt. wt.Relative no. of atomsSimplest ratio
Nitrogen82.351482.3514\dfrac{82.35 }{14} = 5.885.885.88\dfrac{5.88}{5.88} = 1
Hydrogen17.64117.641\dfrac{17.64}{1} = 17.6417.645.88\dfrac{17.64}{5.88} = 3

Simplest ratio of whole numbers = N : H = 1 : 3

Hence, empirical formula is NH3

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