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Mathematics

Find the circumference of the circle whose area is equal to the sum of the areas of three circles with radius 2 cm, 3 cm and 6 cm.

Mensuration

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Answer

Let the radius of resultant circle be r cm.

Given,

Area of resultant circle is equal to the sum of the areas of three circles with radius 2 cm, 3 cm and 6 cm.

⇒ πr2 = π(2)2 + π(3)2 + π(6)2

⇒ πr2 = π[(2)2 + (3)2 + (6)2]

⇒ r2 = 22 + 32 + 62

⇒ r2 = 4 + 9 + 36

⇒ r2 = 49

⇒ r = 49\sqrt{49} = 7 cm.

Circumference of circle = 2πr

= 2×227×72 \times \dfrac{22}{7} \times 7

= 44 cm.

Hence, circumference of circle = 44 cm.

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