Mathematics
Find the area enclosed by the figure (ii) given below. All measurements are in centimeters.
Mensuration
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Answer
From figure,
BJ = 2 + 2 + 2 + 2 = 8 cm.
Area of rectangle ABJK = l × b
= AB × BJ = 2 × 8
= 16 cm2.
From figure,
JH = KH - KI = 6 - 2 = 4 cm.
Area of trapezium FGHI = (sum of parallel sides) × distance between them
= × (FI + GH) × JH
= × (2 + 2) × 4
= × 4 × 4 = 8 cm2.
Area of trapezium CDEF = (sum of parallel sides) × distance between them
= × (CF + DE) × BD
= × (2 + 2) × 4
= × 4 × 4 = 8 cm2.
Total area enclosed = Area of rectangle ABJK + Area of trapezium FGHI + Area of trapezium CDEF
= 16 + 8 + 8
= 32 cm2.
Hence, area enclosed by figure = 32 cm2.
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