Factorise :
a2+b−ab−aa^2 + b - ab - aa2+b−ab−a
1 Like
a2+b−ab−a=a2−ab−a+b=a(a−b)−1(a−b)=(a−b)(a−1)a^2 + b - ab - a\\[1em] = a^2 - ab - a + b\\[1em] = a(a - b) - 1(a - b)\\[1em] = (a - b)(a - 1)a2+b−ab−a=a2−ab−a+b=a(a−b)−1(a−b)=(a−b)(a−1)
Hence, a2+b−ab−a=(a−b)(a−1)a^2 + b - ab - a = (a - b)(a - 1)a2+b−ab−a=(a−b)(a−1).
Answered By
(a2+1)b2−b4−a2(a^2 + 1) b^2 - b^4 - a^2(a2+1)b2−b4−a2
3(2x−y)3+9(2x−y)23(2x -y)^3 + 9(2x - y)^23(2x−y)3+9(2x−y)2
x2+1x2+2−5x−5xx^2 + \dfrac{1}{x^2} + 2 - 5x - \dfrac{5}{x}x2+x21+2−5x−x5
1−(2x−3y)21 - (2x - 3y)^21−(2x−3y)2