Factorise :
3(2x−y)3+9(2x−y)23(2x -y)^3 + 9(2x - y)^23(2x−y)3+9(2x−y)2
3 Likes
3(2x−y)3+9(2x−y)2=3(2x−y)2[(2x−y)+3]=3(2x−y)2(2x−y+3)3(2x -y)^3 + 9(2x - y)^2 = 3(2x - y)^2[(2x - y) + 3]\\[1em] = 3(2x - y)^2(2x - y + 3)3(2x−y)3+9(2x−y)2=3(2x−y)2[(2x−y)+3]=3(2x−y)2(2x−y+3)
Hence, 3(2x−y)3+9(2x−y)2=3(2x−y)2(2x−y+3)3(2x -y)^3 + 9(2x - y)^2 = 3(2x - y)^2(2x - y + 3)3(2x−y)3+9(2x−y)2=3(2x−y)2(2x−y+3).
Answered By
(a+b)2−5(a2−b2)−24(a−b)2(a + b)^2 - 5(a^2 - b^2) - 24(a - b)^2(a+b)2−5(a2−b2)−24(a−b)2
(a2+1)b2−b4−a2(a^2 + 1) b^2 - b^4 - a^2(a2+1)b2−b4−a2
a2+b−ab−aa^2 + b - ab - aa2+b−ab−a
x2+1x2+2−5x−5xx^2 + \dfrac{1}{x^2} + 2 - 5x - \dfrac{5}{x}x2+x21+2−5x−x5
