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Mathematics

Factorise :

3(2xy)3+9(2xy)23(2x -y)^3 + 9(2x - y)^2

Factorisation

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Answer

3(2xy)3+9(2xy)2=3(2xy)2[(2xy)+3]=3(2xy)2(2xy+3)3(2x -y)^3 + 9(2x - y)^2 = 3(2x - y)^2[(2x - y) + 3]\\[1em] = 3(2x - y)^2(2x - y + 3)

Hence, 3(2xy)3+9(2xy)2=3(2xy)2(2xy+3)3(2x -y)^3 + 9(2x - y)^2 = 3(2x - y)^2(2x - y + 3).

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