KnowledgeBoat Logo

Mathematics

Factorise :

(a+b)25(a2b2)24(ab)2(a + b)^2 - 5(a^2 - b^2) - 24(a - b)^2

Factorisation

1 Like

Answer

(a+b)25(a2b2)24(ab)2=a2+b2+2ab5a2+5b224(a2+b22ab)=a2+b2+2ab5a2+5b224a224b2+48ab=28a218b2+50ab=28a2+50ab18b2=2(14a2+25ab9b2)=2(14a2+7ab+18ab9b2)=2(7a(2ab)+9b(2ab))=2(2ab)(7a+9b)(a + b)^2 - 5(a^2 - b^2) - 24(a - b)^2\\[1em] = a^2 + b^2 + 2ab - 5a^2 + 5b^2 - 24(a^2 + b^2 - 2ab)\\[1em] = a^2 + b^2 + 2ab - 5a^2 + 5b^2 - 24a^2 - 24b^2 + 48ab\\[1em] = -28a^2 - 18b^2 + 50ab\\[1em] = -28a^2 + 50ab - 18b^2\\[1em] = 2(-14a^2 + 25ab - 9b^2)\\[1em] = 2(-14a^2 + 7ab + 18ab - 9b^2)\\[1em] = 2(-7a(2a - b) + 9b(2a - b))\\[1em] = 2(2a - b)(-7a + 9b)

Hence, (a+b)25(a2b2)24(ab)2=2(2ab)(9b7a)(a + b)^2 - 5(a^2 - b^2) - 24(a - b)^2 = 2(2a - b)(9b - 7a).

Answered By

1 Like


Related Questions